✨ Math Magic: Square Root Explorer ✨

Exercise 3.7 - Let's uncover the secrets of square roots!

🔍 Problem 1: Find the square root of rational expressions

(i) Find √(400x⁴y¹²z¹⁶ / 100x⁸y⁴z⁴)

1
Step 1: Simplify the expression inside the square root:
√(400x⁴y¹²z¹⁶ / 100x⁸y⁴z⁴) = √(4x⁴⁻⁸y¹²⁻⁴z¹⁶⁻⁴)
2
Step 2: Simplify exponents:
= √(4x⁻⁴y⁸z¹²)
3
Step 3: Take square root of each term:
= √4 × √x⁻⁴ × √y⁸ × √z¹²
4
Step 4: Calculate each square root:
= 2 × x⁻² × y⁴ × z⁶
Final Answer:
= 2y⁴z⁶ / x²

(ii) Find √[(7x² + 2√14x + 2) / (x² - ½x + 1/16)]

1
Step 1: Factor numerator and denominator separately.
2
Step 2: Numerator: 7x² + 2√14x + 2 = (√7x + √2)²
Because (a + b)² = a² + 2ab + b² where a = √7x, b = √2
3
Step 3: Denominator: x² - ½x + 1/16 = (x - ¼)²
Perfect square pattern: (a - b)² = a² - 2ab + b²
4
Step 4: Now the expression becomes:
√[(√7x + √2)² / (x - ¼)²]
Final Answer:
= (√7x + √2) / (x - ¼)

(iii) Find √[121(a+b)⁸(x+y)⁸(b-c)⁸ / 81(b-c)⁴(a-b)¹²(b-c)⁴]

1
Step 1: Combine like terms in denominator:
Denominator: 81(b-c)⁴⁺⁴(a-b)¹² = 81(b-c)⁸(a-b)¹²
2
Step 2: Rewrite the expression:
√[121(a+b)⁸(x+y)⁸(b-c)⁸ / 81(a-b)¹²(b-c)⁸]
3
Step 3: Cancel (b-c)⁸ terms:
= √[121(a+b)⁸(x+y)⁸ / 81(a-b)¹²]
4
Step 4: Take square root of each term:
= 11(a+b)⁴(x+y)⁴ / 9(a-b)⁶
Final Answer:
= 11(a+b)⁴(x+y)⁴ / 9(a-b)⁶

🔢 Problem 2: Find the square root of expressions

(i) Find √(4x² + 20x + 25)

1
Step 1: Recognize perfect square trinomial pattern:
a² + 2ab + b² = (a + b)²
2
Step 2: Identify terms:
4x² = (2x)², 25 = 5², 20x = 2 × 2x × 5
3
Step 3: Rewrite as perfect square:
4x² + 20x + 25 = (2x + 5)²
Final Answer:
√(4x² + 20x + 25) = 2x + 5

(ii) Find √(9x² - 24xy + 30xz - 40yz + 25z² + 16y²)

1
Step 1: Group terms to find perfect square pattern.
2
Step 2: Rearrange terms:
9x² - 24xy + 16y² + 30xz - 40yz + 25z²
3
Step 3: First three terms form perfect square:
9x² - 24xy + 16y² = (3x - 4y)²
4
Step 4: Last three terms have common factor:
30xz - 40yz + 25z² = 5z(6x - 8y + 5z)
5
Step 5: Notice 6x-8y is 2(3x-4y):
= 5z[2(3x-4y) + 5z] = 10z(3x-4y) + 25z²
Final Answer:
The expression is (3x - 4y + 5z)², so √... = 3x - 4y + 5z

(iii) Find √[(4x² - 9x + 2)(7x² - 13x - 2)(28x² - 3x - 1)]

1
Step 1: Factor each quadratic expression.
2
Step 2: Factor first expression:
4x² - 9x + 2 = (4x - 1)(x - 2)
3
Step 3: Factor second expression:
7x² - 13x - 2 = (7x + 1)(x - 2)
4
Step 4: Factor third expression:
28x² - 3x - 1 = (7x + 1)(4x - 1)
5
Step 5: Multiply them together:
(4x-1)(x-2) × (7x+1)(x-2) × (7x+1)(4x-1)
6
Step 6: Rearrange terms:
= [(4x-1)(7x+1)(x-2)]²
Final Answer:
√... = (4x - 1)(7x + 1)(x - 2)

(iv) Find √[(2x² + 17/6x + 1)(3/2x² + 4x + 2)(4/3x² + 11/3x + 2)]

1
Step 1: Multiply each expression by appropriate factor to eliminate fractions.
2
Step 2: First expression ×6:
12x² + 17x + 6
3
Step 3: Second expression ×2:
3x² + 8x + 4
4
Step 4: Third expression ×3:
4x² + 11x + 6
5
Step 5: Factor each:
(3x+2)(4x+3), (3x+2)(x+2), (x+2)(4x+3)
6
Step 6: Multiply them:
(3x+2)²(4x+3)²(x+2)²
Final Answer:
√... = (3x + 2)(4x + 3)(x + 2) / √(6×2×3) = (3x+2)(4x+3)(x+2)/6
y⁴
=
(a+b)²
π